Linear Circuit Analysis
1. Introduction
2. Basic Concepts
- Charge, current, and voltage
- Power and energy
- Linear circuits
- Linear components
- Nodes and loops
- Series and parallel
- R, L & C combinations
- V & I combinations
3. Simple Circuits
- Ohm's law
- Kirchhoff's current law
- Kirchhoff's voltage law
- Single loop circuits
- Single node-pair circuits
- Voltage division
- Current division
4. Nodal and Mesh Analysis (DC)
5. Additional Analysis Techniques (DC)
- Superposition
- Source transformation
- The $V_{test}/I_{test}$ method
- Norton equivalent
- Thévenin equivalent
- Max power transfer
- DC analysis of L & C
6. AC Analysis
7. Magnetically Coupled Circuits
8. Polyphase Systems
9. Operational Amplifiers
10. Laplace Transforms
11. Time-Dependent Circuits
- Introduction
- Inductors and capacitors
- First-order transients
- Second-order transients
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Parallel RLC circuits
Series RLC circuits - Nodal analysis
- Mesh analysis
- Laplace transforms
- Additional techniques
12. Two-Port Networks
Appendix
Ideal Operational Amplifiers
An ideal OpAmp is an OpAmp with infinite input resistance $R_{in}=\infty$, zero output resistance $R_{out}=0$, and infinite gain $A=\infty$. Many commercial OpAmps have relatively high input resistance (usually $\gt 1 \: {\class{mjunit}M\Omega}$), low output resistance ($\lt 100 \: {\class{mjunit}\Omega}$), and very high gain ($\gt 10^6$), and can often be approximated as ideal OpAmps.
How to Solve Problems with Ideal OpAmps
Since an OpAmp has four terminals, its electrical behavior is described using three equations. For comparison, a resistor (which has two terminals) is characterized by a single equation (Ohm’s law), while a transistor (which has three-terminals) requires two equations (the Ebers–Moll equations). Note that in this count we do not include the Kirchhoff’s Current Law (KCL) equation, which states that the algebraic sum of the currents leaving the terminals of any device must be zero. If we had included KCL, the number of independent equations that describe a device is equal to the number of terminals. Using the notations shown in Fig. 2, we have:
- Infinite input resistance which implies the following two equations
- Infinite gain which implies that
Using nodal analysis
It is usually easier to write the nodal equations for a circuit containing OpAmps than the mesh equations. When using nodal analysis, we follow the same algorithm presented in the DC and AC circuit analysis sections. In particular, we:
A. Write the voltage constrained equations for each voltage source (one equation per source). Also, add a voltage constrained equation for each OpAmp, by writing that the potential of the positive input terminal equals the potential of the negative terminal, $v_{+}=v_{-}$ (which results from the infinite gain condition).
B. Write one equation for each control variable.
C. Write KCL equations for regular nodes and use that the currents going through the input terminals of the OpAmps are equal to zero (the infinite input resistance condition). Notice that the node containing the output terminal of the OpAmp is not a regular node and we skip writing KCL for this node.
D. Write KCL equations for supernodes.
Then, we solve the above system of nodal analysis equations and compute the values of the nodal potentials and control variables. After this, we write the equations for the sought variables as a function of the nodal potentials.
A few examples with ideal OpAmps are presented below.
Computing gain, $G$
A common question that arises when analyzing circuits with OpAmps is the computation of the gain, which is defined as $$\begin{equation}G=\frac{V_{out}}{V_{in}}\end{equation}$$ where $V_{out}$ and $V_{in}$ are the output and input voltages of the circuit. The output voltage is usually the voltage across a load impedance (for example, a speaker in an audio amplifier). Since OpAmps are linear devices, the output voltage is proportional to the input voltage and the gain does not depend on $V_{in}$.
Next, we present a few common configurations with OpAmps. Problems with OpAmps can often be solved by identifying the configuration of the OpAmp in the circuit (i.e. inverter or follower) and applying the equations of the gain, which are derived below.
Inverter
A standard configuration of OpAmps is the inverting amplifier shown in Fig. 3. The nodal equations for nodes $v_1$, $v_2$, and $v_3$ are $$\begin{equation}V_{in}=v_2\end{equation}$$ $$\begin{equation}v_1=0\end{equation}$$ $$\begin{equation}\frac{v_1-v_2}{R_2} + \frac{v_1-v_3}{R_1}=0\end{equation}$$ The above system of equations can be solved for $v_1$, $v_2$, and $v_3$. Then, we can compute the sought variable $V_{out}=v_3$ and obtain $$\begin{equation}\frac{V_{out}}{V_{in}}=-\frac{R_2}{R_1} \end{equation}$$ We notice that the total gain of the inverter configuration depends only on the value of resistors $R_1$ and $R_2$ and $V_{out}$ is inverted with respect to the input signal.
Follower
Another standard configuration of OpAmps is the non-inverting amplifier (also called a voltage follower) Fig. 4. The nodal equations for nodes $v_1$, $v_2$, and $v_3$ are $$\begin{equation}V_{in}=v_1\end{equation}$$ $$\begin{equation}v_1=v_3\end{equation}$$ $$\begin{equation}\frac{v_3-v_2}{R_2} + \frac{v_3}{R_1}=0\end{equation}$$ The above system of equations can be solved for $v_1$, $v_2$, and $v_3$. Then, we can compute the sought variable $V_{out}=v_3$ and obtain $$\begin{equation}\frac{V_{out}}{V_{in}}=1+\frac{R_2}{R_1}\end{equation}$$ We notice that the total gain of the follower configuration depends only on the values of resistors $R_1$ and $R_2$, and $V_{out}$ is directly proportional to the input signal.
Unit-gain amplifier
A particular case of the follower configuration is the unit-gain amplifier shown in Fig. 5. In this case $R_2=0$, $R_1=\infty$ and $$\begin{equation}V_{out}=V_{in}\end{equation}$$ An important benefit of unit-gain amplifiers is their very large input impedance (infinite for an ideal OpAmp), because they draw no current from the input source.
Notice that we could also build a "negative" unit gain amplifier using the inverter configuration.
Examples of Solved Problems
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DC OpAmps (numerical)
Circuit with 1 ideal OpAmp, follower (numerical)
Circuit with 1 ideal OpAmp (numerical)
Circuit with 2 ideal OpAmps in series (numerical)
Circuit with 2 ideal OpAmps in parallel (numerical)
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DC OpAmps (gain calculation)
Circuit with 1 ideal OpAmp, follower (numerical gain calculation)
Circuit with 1 ideal OpAmp, inverter (numerical gain calculation)
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DC OpAmps (analytical)
Circuit with 1 ideal OpAmp, follower (analytical)
Circuit with 1 ideal OpAmp, inverter (analytical)
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DC OpAmps (design)
Circuit with 1 ideal OpAmp, follower (numerical design)
Circuit with 1 ideal OpAmp, inverter (numerical design)
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DC OpAmps (numerical)
Circuit with 1 ideal OpAmp, follower with unit gain (numerical)
Circuit with 1 ideal OpAmp, follower (numerical)
Circuit with 1 ideal OpAmp, inverter (numerical)
Circuit with 1 ideal OpAmp (numerical)
Circuit with 2 ideal OpAmps in series (numerical)
Circuit with 2 ideal OpAmps in parallel (numerical)
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DC OpAmps (gain calculation)
Circuit with 1 ideal OpAmp, follower with unit gain (numerical gain calculation)
Circuit with 1 ideal OpAmp, follower (numerical gain calculation)
Circuit with 1 ideal OpAmp, inverter (numerical gain calculation)
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DC OpAmps (analytical)
Circuit with 1 ideal OpAmp, follower with unit gain (analytical)
Circuit with 1 ideal OpAmp, follower (analytical)
Circuit with 1 ideal OpAmp, inverter (analytical)
Circuit with 1 ideal OpAmp (analytical)
Circuit with 2 ideal OpAmps in series (analytical)
Circuit with 2 ideal OpAmps in parallel (analytical)
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DC OpAmps (design)
Circuit with 1 ideal OpAmp, follower (numerical design)
Circuit with 1 ideal OpAmp, inverter (numerical design)
Circuit with 1 ideal OpAmp (numerical design)
See also
Non-ideal OpAmps
Nodal analysis